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(05.02)A doghouse is to be built in the shape of a right trapezoid, as shown below. What is the area of the doghouse?

A right trapezoid with top side 7 feet and height 7 feet. The bottom side is extended to the right with 3 more feet.
24.5 square feet
59.5 square feet
70 square feet
147 square feet

Respuesta :

JJNinja9
The answer is 59.5 square feet. To solve this, you need to know the formula for the area of a trapezoid, which is: A= h(b1+b2/2). This means that the Area is equal to the height multiplied by base 1 + base 2 divided by 2. So the equation would look like this:

A= 7(7+10)
    -------------
           2

A= 7(17)
    -----------
         2
A= 119
    ----------
        2
A= 59.5 square feet
calculista

Answer:

The area of the doghouse is [tex]59.5\ ft^{2}[/tex]

Step-by-step explanation:

we know that

The area of trapezoid is equal to

[tex]A=\frac{1}{2}(b1+b2)h[/tex]

where

b1,b2 are the parallel bases of trapezoid

h is the height of trapezoid

in this problem we have

[tex]b1=7\ ft[/tex]

[tex]b2=7+3=10\ ft[/tex]

[tex]h=7\ ft[/tex]

substitute

[tex]A=\frac{1}{2}(7+10)7=59.5\ ft^{2}[/tex]


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