We have that the value of f, rounded to the nearest hundredth.
f_1=0.02
f_2=0.009
f_3=0.009
From the question we are told that
d(v)= \frac{2.15v^2}{64.4f}
Generally the equation for the f is mathematically given as
f= \frac{2.15v^2}{64.4*d(v)}
Therefore
For v=20 and f=38
f= \frac{2.15(20)^2}{64.4*(38)(20)}
f=0.02
For v=30 and f=86
f=\frac{2.15(30)^2}{64.4*(86)(30)}
f=0.01
For v=40 and f=153
f=\frac{2.15(40)^2}{64.4*(153)(40)}
f=0.009
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