contestada

a car in a drag race started from rest and accelerated constantly to a velocity of 50 m/s when it reached the end of a 500 m road. What was the cars rate of acceleration?

Respuesta :

Use the kinematic equation, [tex]v _{f} ^{2} = v _{o} ^{2} + 2a ( x_{f} - x_{o} ) [/tex] 
use your givens, v initial is 50m/s, v final would be 0m/s since the car is coming to a rest, x final would be 500m, x intial would be 0m, and you are looking for your acceleration. plug in your givens into your equation:
 [tex](50) ^{2} = (0) ^{2} + 2(a)(500)[/tex]

so, by solving for a, you would get 2.5m/s[tex] ^{2} [/tex]
valeriagonzalez0213

Answer:

The acceleration of the car is [tex]2.5\frac{m}{s^{2} }[/tex]

Explanation:

Kinematics of the problem:

The car moves with uniform accelerated movement, then, We use the acceleration equation for this type of movement:

[tex]a=\frac{1}{2*d} (v_{f} ^{2} -v_{i} ^{2} )[/tex]  Formula 1

vf: final speed=[tex]50\frac{m}{s}[/tex]

vi: initial speed=0

d=distance traveled by the car=500m

Acceleration calculating:

We replace known information in the equation 1:

[tex]a=\frac{50^{2} -0}{2*500}[/tex]

[tex]a=\frac{2500}{1000}[/tex]

[tex]a=2.5\frac{m}{s^{2} }[/tex]

Answer:

The acceleration of the car is [tex]2.5\frac{m}{s^{2} }[/tex]

Otras preguntas