Answer:
Q = 440 J
Explanation:
Given data:
Heat required = ?
Initial temperature = 25°C
Final temperature = 40°C
Mass in gram = 20 g
Specific heat capacity = 1.1 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 40°C - 20°C
ΔT = 20°C
Q = 20 g×1.1 J/g.°C × 20°C
Q = 440 J
