Respuesta :
Answer:The solution contains 0.50 mol or 55 g of CaCl2 . You know there are 2.0 mol of CaCl2 in 1 L of solution. (40.08 + 2 × 35.45) g=(40.08 + 70.90)
g=110.98 g
Explanation:
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110.98 grams of CaCl₂ is there present in 2.0 M CaC₂.
What is calcium chloride?
Calcium chloride is made up of calcium and chloride.
Given, that the solution contain 250 mL of 2.0 M CaCl2
You know there are 2.0 mol of CaCl2 in 1 L of solution.
(40.08 + 2 × 35.45) g
= (40.08 + 70.90)
=110.98 g
Thus, 110.98 grams of CaCl₂ is there present in 2.0 M CaC₂.
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