What is the equation in point-slope form of the line that passes through the points (7, 5) and (−4, −1)?
y + 1 = 6/7 (x+4)
y + 4 = 11/6 (x+1)
y − 1 = 6/11 (x−4)
y + 1 = 6/11 (x+4)

Respuesta :

gmany

The point-slope form:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

(x₁, y₁) - point

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have the points (7, 5) and (-4, -1). Substitute:

[tex]m=\dfrac{-1-5}{-4-7}=\dfrac{-6}{-11}=\dfrac{6}{11}[/tex]

[tex]y-(-1)=\dfrac{6}{11}(x-(-4))\\\\\boxed{y+1=\dfrac{6}{11}(x+4)}[/tex]