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Answer:
Baby 1 goes to parent 2 and baby 2 goes to parent 1. My results for the first Punnett square for parent 1 was 100% AO. My results for the second Punnett square is 50% AO, 50% OO. My results for the first punnett squares for parent 2 is 50% AA, 50% AB, and the results for the second punnett square is 25% AA, 25% AO, 25% AB, 25% BO.
Explanation:
Baby 1 belongs to parents 2, whereas baby 2 belongs to parents 1.
In this case, it is important to have into account that the ABO blood type is inherited in an autosomal codominant fashion.
The A and alleles B are codominant and therefore both alleles are expressed, thereby if an individual inherits allele A from one parent and allele B from another parent, he/she has blood type AB. It is the case for baby 1 (genotype AB).
Conversely, the A and B alleles are dominant on the allele O, which is recessive. It is the case for baby 2 (genotype OO).
The genotypes of the parents are:
Parents 1:
- Mom is heterozygous type A (genotype AO) and the dad is type O (genotype OO).
Parents 2:
- Mom is heterozygous type A (genotype AO) and dad has AB (genotype AB).
Parents 2 can produce these gametes:
- Mom: 1/2 A; 1/2 O
- Dad: 1/1 O
So their offspring can be:
A O
O AO OO
F1: 1/2 AO; 1/2 OO
In consequence, baby 2 (genotype OO) belongs to parents 1
Parents 2 can produce these gametes:
- Mom: 1/2 A; 1/2 O
- Dad: 1/2 A; 1/2 B
So their offspring can be:
A O
A AA AO
B AB BO
F1: 1/4 AA; 1/4 AO; 1/4 AB; 1/4 BO
In consequence, baby 1 (genotype AB) belongs to parents 2
In conclusion, baby 1 belongs to parents 2, whereas baby 2 belongs to parents 1.
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