Answer:
New force = 2.688 N
Explanation:
Given that,
Two charged particles exert a force of 0.042 N on each other.
Let the initial distance is r. Later the particles are moved such that they are now one-eighth as far apart.
New distance, r' = (r/8)
The force between particles is given by :
[tex]F'=\dfrac{kq_1q_2}{r'^2}\\\\F'=\dfrac{kq_1q_2}{(\dfrac{r}{8})^2}\\\\F'=\dfrac{kq_1q_2}{\dfrac{r^2}{64}}\\\\F'=64\times \dfrac{kq_1q_2}{r^2}\\\\F'=64\times F\\\\F'=64\times 0.042\\\\F'=2.688\ N[/tex]
So, the new force is 2.688 N.
