Answer:
The mass of the fish is 18.1 kg.
Explanation:
Given;
weight of the fish, F = 108 N
extension of the spring by the given weight, x = 14 cm = 0.14 m
First, determine the elastic constant of the spring by applying Hook's law;
F = kx
where;
k is the spring constant
k = F/x
k = 108 / 0.14
k = 771.43 N/m
When the spring is stretched to 23cm, the mass of the fish is calculated as follows;
[tex]F = mg = Kx\\\\m = \frac{Kx}{g} \\\\m = \frac{771.43\times 0.23}{9.8} \\\\m = 18.1 \ kg[/tex]
Therefore, the mass of the fish is 18.1 kg.
