Respuesta :

The diagram of the triangle is missing, so i have attached it.

Answer:

PN = 28

QP = 14

Step-by-step explanation:

We are told that QN = 42

Since P is the centroid, by inspection we can see that;

PN = ⅔QN

Thus, PN = ⅔ × 42

PN = 28

Also, we see that PN + QP = QN

Thus;

28 + QP = 42

QP = 42 - 28

QP = 14

Following are the calculation on the PN and QP:

  • Mp, Lp, and NQ are indeed the central lines of a large briangle MNL, according the problem. Particles entersect at point P.
  • This is referred to as a baryc enter of a friangle.
  • And has the quality Np= 2PQ, therefore we can obtain it.

              [tex]Np = \frac{2}{3} QN\\\\ PQ = \frac{1}{3} QN \\\\NP=\frac{2}{3} \times 42= 28 \\\\PQ= \frac{1}{3} \times 42 = 14 \\\\[/tex]  

  • When you are aware, the point p is indeed the barycenter of a large triangle, and this is an important trait.

Learn more:

brainly.com/question/80336

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