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There are 40 cows and chicken in Fred's farmyard.
One afternoon, Fred counted and found that there
were 100 legs in all. How many cows and chickens
are there? Solve this problem by writing and solving
a system of equations.

Respuesta :

greenforestaz

Step-by-step explanation:

step 1. let cows = c and chickens = h

step 2. c + h = 40

step 3. 4c + 2h = 100 (cows have 4 legs and chickens have 2)

step 4. solve the system. multiply step 2 by 2 and subtract from step 3

step 5. 2c = 20 or c = 10 (10 cows)

step 6. h = 30 (30 chickens)

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