The poisonous gas hydrogen sulfide, H2S, can be neutralized with a base such as sodium hydroxide,
NaOH. The unbalanced equation for this reaction follows:
NaOH(aq) + H25(e) → Na2S(aq) + H2O(1)
A student who was asked to balance this equation wrote the following:
Na2OH(aq) + H2S(g) → Na2S(aq) + H2O(
Is this equation balanced? Is it correct? Explain why or why not, and supply the correct balanced
equation if necessary.

Question

03-03-2021
Chemistry

contestada

The poisonous gas hydrogen sulfide, H2S, can be neutralized with a base such as sodium hydroxide,
NaOH. The unbalanced equation for this reaction follows:
NaOH(aq) + H25(e) → Na2S(aq) + H2O(1)
A student who was asked to balance this equation wrote the following:
Na2OH(aq) + H2S(g) → Na2S(aq) + H2O(
Is this equation balanced? Is it correct? Explain why or why not, and supply the correct balanced
equation if necessary.

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KingTrator KingTrator · Answer 1 · 2021-03-03T17:29:31+01:00

Answer:

It's not correct. For balancing, we need to put the coefficients in the molecule, not in the athom. Because if you do this, you're creating another molecule, instead of a balacing, for which the reaction may not happen - but anyway, it would be another reaction.

The correct balacing is:

2NaOH + 1H2S → 1Na2S + 2H2O

Explanation:

Look: Na2OH does not even exist. OH has only one free link, so he can't - in normal conditions - make another one with any athom. That's why we should write 2NaOH instead of Na2OH. The first means "2 mols of NaOH".