Answer: There are 4.375 moles in 2.5 L of 1.75 M [tex]Na_2CO_3[/tex]
Explanation:
To calculate the number of moles for given molarity, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
Molarity of solution = 1.75 M
Volume of solution = 2.5 L
Putting values in equation , we get:
[tex]1.75M=\frac{\text{Moles of} Na_2CO_3}{2.5L}\\\\\text{Moles of }Na_2CO_3=1.75mol/L\times 2.5L=4.375mol[/tex]
