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You are given 127 g H2CO3 (Carbonic Acid) and a volume of 800 mL of water, what will the final concentration of your solution be? (The final unit is the Molar (M), but do not include it.) (Round to 3 decimal places.)

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Answer:

2.562

Explanation:

First we convert 127 g of H₂CO₃ to moles, using its molar mass:

  • 127 g ÷ 62 g/mol = 2.05 mol H₂CO₃

Then we convert 800 mL to L:

  • 800 mL / 1000 = 0.800 L

Finally we can calculate the concentration of the solution as molarity:

  • molarity = moles / liters
  • molarity = 2.05 mol / 0.800 L = 2.562 M

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