Respuesta :

Hrishii

Answer:

[tex] \frac{7 {n}^{2} - 41n + 8 }{ {n}^{2} - 1 } [/tex]

Step-by-step explanation:

[tex] \frac{7n}{n + 1} + \frac{8}{n - 7} \\ \\ = \frac{7n(n - 7) + 8(n + 1)}{(n + 1)(n - 1)} \\ \\ = \frac{7 {n}^{2} - 49n + 8n + 8 }{ {n}^{2} - 1 } \\ \\ = \frac{7 {n}^{2} - 41n + 8 }{ {n}^{2} - 1 } [/tex]

mhanifa

Answer:

Simplified:

  • [tex]\frac{7n}{n + 1} + \frac{8}{n - 7}[/tex]   =
  • [tex]\frac{7n(n - 7) + 8(n + 1)}{(n + 1)(n - 7)}[/tex]   =
  • [tex]\frac{7n^2 - 49n + 8n + 8}{n^2 + n - 7n - 7}[/tex]   =
  • [tex]\frac{7n^2 - 41n + 8}{n^2 - 6n - 7}[/tex]

This can be further simplified if required

  • [tex]\frac{7n^2 - 42n -49 + n + 57}{n^2 - 6n - 7}[/tex] =
  • [tex]7 + \frac{n + 57}{n^2 - 6n - 7}[/tex]