Respuesta :
Answer:
See Below.
Step-by-step explanation:
We want to verify the trigonometric identity:
[tex]\cos^2(5x)-\sin^2(5x)=\cos(10x)[/tex]
For simplicity, we can let u = 5x. Therefore, by substitution, we acquire:
[tex]\cos^2(u)-\sin^2(u)[/tex]
Recall the double-angle identity formula(s) for cosine:
[tex]\displaystyle \begin{aligned} \cos(2x)&=\cos^2(x)-\sin^2(x)\\&=2\cos^2(x)-1\\&=1-2\sin^2(x)\end{aligned}[/tex]
Therefore, our identity becomes:
[tex]=\cos(2u)[/tex]
Back-substitute:
[tex]=\cos(2(5x))=\cos(10x)\stackrel{\checkmark}{=}\cos(10x)[/tex]
Hence proven.
cos²A - sin²A = cos2A, this is a general indentity where A can have any random value x/2, y/3, 1/8, 8, 9 etc.
Replacing A with 5x:
=> cos²(5x) - sin²(5x) = cos²(10x)
Moreover,
cos(A + B) = cosAcosB - sinAsinB.
When A = B,
cos(A + A) = cosAcosA - sinAsinA
cos2A = cos²A - sin²A
You can do the same with 5x.
cos(10x) = cos(5x + 5x)
cos(10x) = cos(5x)cos(5x) - sin(5x)sin(5x)
cos(10x) = cos²(5x) - sin²(5x)