Answer:
There are 0.16 g of sulphur in 3.0 × 10²¹ atoms.
Explanation:
One mole of a substance contains 6.02 × 10²³ particles
One mole of sulphur atom contains 6.02 × 10²³ atoms
Number of moles of sulphur present in 3.0 × 10²¹ atoms = 3.0 ×10²¹/6.02 10²³
Number of moles of sulphur atom = 0.00498 moles of sulphur atom
The mole of a substance is related to its mass by a quantity known as molar mass which is defined as the mass of one mole of that substance.
Molar mass of sulphur atom = 32 grams per mole (g/mol)
Mass of 0.00498 moles of sulphur atom = 0.00498 moles × 32 g/mol
Mass of sulphur = 0.16 g
Therefore, there are 0.16 g of sulphur in 3.0 × 10²¹ atoms.
