Answer:
The answer is "Including all three studies of 0s to 2s, that shift in momentum is equal".
Explanation:
Its shift in momentum doesn't really depend on the magnitude of its cars since the forces or time are similar throughout all vehicles.
Let's look at the speed of the car
[tex]F = m a\\\\a =\frac{F}{m}[/tex]
We use movies and find lips
[tex]\to v = v_0 + a t\\\\\to v = v_0 + (\frac{F}{m}) t[/tex]
The moment is defined by
[tex]\to p = m v[/tex]
The moment change
[tex]\Delta p = m v - m v_0[/tex]
Let's replace the speeds in this equation
[tex]\Delta p = m (v_0 + \frac{F}{m t}) - m v_0\\\\\Delta p = m v_0 + F t - m v_0\\\\\Delta p = F t[/tex]
They see that shift is not directly proportional to the mass of cars since the force and time were the same across all cars.
