Sally has constructed a concentration cell to measure Ksp for MCln. She constructs the cell by adding 2 mL of 0.05 M M(NO3)n to one compartment of the microwell plate. She then makes a solution of MCln by adding KCl to M(NO3)n. She adds 6.380 mL of the resulting mixture to a second compartment of the microwell plate.

Sally knows n (the charge on the metal ion) = +2
She has already calculated [Mn+] in the prepared MCln solution using the Nernst equation. [Mn+] = 8.279 M

Required:
How many moles of [Cl-] must be dissolved in that compartment?

Question

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AbsorbingMan AbsorbingMan · Answer 1 · 2021-04-05T08:27:43+02:00

Answer:

0.1056 mole

Explanation:

As Sally knows that the charge on the metal ion is n = +2

[tex]$MCl_n=MCl_2$[/tex]

In that compartment [tex]$[M^{n+}]=[m^{2+}]=8.279 \ M$[/tex]

The volume of the [tex]$MCl_n$[/tex] taken in that compartment = 6.380 mL

So, the number of moles of [tex]$M^{2+} = 8.279 \times 6.380$[/tex]

= 52.82 m mol

= 0.05280 mol

[tex]$MCl_n \rightarrow M^{n+}+nCl^-$[/tex]

But n = 2

Therefore, moles of [tex]$Cl^-$[/tex] = 2 x moles of [tex]$M^{n+}$[/tex]

= 2 x 0.05282

= 0.1056 mole