Respuesta :
Answer:
A) H0: σ₁²-σ₂²= 0 against the claim Ha: σ₁²-σ₂²≠0
B) t= 0.3543860
C) t≥ t∝/2 ( d.f)=2.024394
D)1) There is no evidence of a difference in the variability of the amount of time required to reach a customer service representative between the two hotels.
Step-by-step explanation:
The claim is that there is evidence of a difference in the variability of the amount of time required to reach a customer service representative between the two hotels which is the
alternate hypothesis
The null hypothesis is the reverse of the alternate hypothesis
The null hypothesis is that there is not enough evidence of a difference in the variability of the amount of time required to reach a customer service representative between the two hotels.
Part A) H0: σ₁²-σ₂²= 0 against the claim Ha: σ₁²-σ₂²≠0
Part B) t= x1`-x2`/ sqrt ( s₁²/n₁ + s₂²/n₂)
t= 2.214- 2.0115/ sqrt ( 2.951657/20+ 3.57855/20)
t= 0.2025/ sqrt(0.14758285 + 0.1789275)
t= 0.2025/0.5714108
t= 0.3543860
Part C) for 2 tailed test the critical value of t is obtained by
t≥ t∝/2 ( d.f)= ± 2.024394
We look at the table with values 0.025 as ∝/2= 0.05/2= 0.025
in the degrees of freedom 38
The d.f = n1+n2-2= 20+20-2= 40-2= 38
Part D) Since the calculated value of t= 0.3543860 does not fall in the critical region t≥ t∝/2 ( d.f)= ± 2.024394 we conclude that H0 is true and accept the null hypothesis.
So option 1 is correct
1) There is no evidence of a difference in the variability of the amount of time required to reach a customer service representative between the two hotels.