Answer:
11.8 L
Explanation:
Step 1: Write the balanced reaction between hydrogen and nitrogen
3 H₂(g) + N₂(g) = 2 NH₃(g)
Step 2: Calculate the moles corresponding to 35.4 L of H₂
At STP, 1 mole of H₂ occupies 22.4 L.
35.4 L × 1 mol/22.4 L = 1.58 mol
Step 3: Calculate the moles of N₂ required to react with 1.58 moles of H₂
The molar ratio of H₂ to N₂ is 3:1. The moles of N₂ required are 1/3 × 1.58 mol = 0.527 mol
Step 4: Calculate the volume occupied by 0.527 moles of N₂ at STP
At STP, 1 mole of N₂ occupies 22.4 L.
0.527 mol × 22.4 L/1 mol = 11.8 L
