Answer:
12.4 g N₂O₂
General Formulas and Concepts:
Chemistry
Atomic Structure
- Reading a Periodic Table
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
Explanation:
Step 1: Define
[Given] 1.24 × 10²³ molecules N₂O₂
[Solve] grams N₂O₂
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of N - 14.01 g/mol
[PT] Molar Mass of O - 16.00 g/mol
Molar Mass of N₂O₂ - 2(14.01) + 2(16.00) = 60.02 g/mol
Step 3: Convert
- [DA] Set up: [tex]\displaystyle 1.24 \cdot 10^{23} \ molecules \ N_2O_2(\frac{1 \ mol \ N_2O_2}{6.022 \cdot 10^{23} \ molecules \ N_2O_2})(\frac{60.02 \ g \ N_2O_2}{1 \ mol \ N_2O_2})[/tex]
- [DA] Divide/Multiply [Cancel out units]: [tex]\displaystyle 12.3588 \ g \ N_2O_2[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
12.3588 g N₂O₂ ≈ 12.4 g N₂O₂