Respuesta :

dsdrajlin

Answer:

63.7 °C

Explanation:

Step 1: Given and required data

  • Mass of water (m): 75.4 g
  • Initial temperature (T₁): 12.6 °C
  • Absorbed heat (Q): 3.85 kcal
  • Specific heat capacity of water (c): 1 cal/g.°C

Step 2: Calculate the final temperature of the water (T₂)

We will use the following expression.

Q = c × m × (T₂ - T₁)

T₂ = Q/c × m + T₁

T₂ = 3.85 × 10³ cal/(1 cal/g.°C) × 75.4 g + 12.6 °C = 63.7 °C

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