Answer:
The length of the arc is 6.28 inches
Step-by-step explanation:
Given
[tex]\theta = 60[/tex]
Required
Length of the arc
This is calculated as:
[tex]L = \frac{\theta}{360} * 2\pi r[/tex]
So, we have:
[tex]L = \frac{60}{360} * 2 * \frac{22}{7} * 6[/tex]
[tex]L = \frac{15840}{2520}[/tex]
[tex]L = 6.28in[/tex]