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The sum of two numbers is 73. Twice the smaller number is one less than the larger number. The smaller number is
A) 24 B) -24 C) 74/3 D) -74/3

Respuesta :

Answer:

The big number is 41 and the small number is 32.

Step-by-step explanation:

b + s = 73

2b - s = 50        Add these equations together

3b = 123            Divide both sides by 3

b = 41

Now plug this into the first equation to find s

41 + s = 73

-41       - 41

s = 32

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