Answer:
0.02degrees
Step-by-step explanation:
Given the following
Length of the river (adjacent) = 1352km = 1352000m
Height of the source (opposite) = 453m
Required
angle of elevation theta
Using the SOH CAH TOA identity
tan theta = opposite/adjacent
tan theta = 453/1352000
tan theta = 0.0003351
theta = arctan(0.0003351)
theta = 0.02 degrees
Hence the Brazos river flows at an angle of 0.02degrees to the nearest hundredth