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An object moving initially with a velocity of 12m/s is uniformly accelerated at rate of 3 m/s^2. What is its velocity after 8 seconds acceleration? If it started at position 8 m. What is its position after 8s?

Respuesta :

Answer:

36 m/s is v2

Explanation:

formula is v2 = v1+ (a)(t)

v2 is unknown so that stays as the variable, v1 = 12 a = 3 t = 8

so the equation would be

v2 = 12 + 3x8

v2 = 12 + 24

v2 = 36

hope this helps!

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