Answer:
The magnitude of the resultant force is: 27.40 pounds
Step-by-step explanation:
Given
[tex]F_1 = 45[/tex]
[tex]F_2 = 50[/tex]
[tex]\theta = 33[/tex]
Required
The magnitude of the resultant vector
To do this, we apply cosine formula
[tex]R^2 = F_1^2 + F_2^2 - 2 * F_1 * F_2 * \cos(\theta)[/tex]
This gives:
[tex]R^2 = 45^2 + 50^2 - 2 * 45 * 50 * \cos(33)[/tex]
[tex]R^2 = 2025+ 2500 - 4500* 0.8387[/tex]
[tex]R^2 = 2025+ 2500 - 3774.15[/tex]
[tex]R^2 = 750.85[/tex]
Take square roots of both sides
[tex]R = \sqrt{750.85\\[/tex]
[tex]R = 27.40[/tex]
