please help me
consider the following equations :

A) 2x+3y=12
B) 2x+3y=6

How will the graphs of the two equations differ from each other ?

Respuesta :

they will have different x and y intercepts

A. has xint of  (6,0) and yint of (0,4)
B. has xint of (3,0) and yint of (0,2)

The graphs of the two equations differ from each other because they have different y intercepts.

A linear equation is in the form:

y = mx + b;

where m is the slope, b is the y intercept and y, x are variables.

The first equation is given by:

2x + 3y = 12

3y = -2x + 12

y = (-2/3)x + 12       (1)

Hence the first equation has a slope of -2/3 and y intercept of 12.

The second equation is given by:

2x + 3y = 6

3y = -2x + 6

y = (-2/3)x + 6       (2)

Hence the second equation has a slope of -2/3 and y intercept of 6.

The graphs of the two equations differ from each other because they have different y intercepts.

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