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Given 32.0 g of water, if we see a temperature change from 25.0°C to 20.0°C, then how much heat energy (q) is transferred from the water?

(The specific heat of water is 4.184 J/g°C )

Respuesta :

Answer:

Q = 669.44 J

Explanation:

Given that,

Mass of water, m = 32 g

The temperature change from 25.0°C to 20.0°C.

We need to find the amount of heat energy transferred. Let it is Q. We know that,

[tex]Q=mc\Delta T[/tex]

Where

c is the specific heat of water

Put all the values,

[tex]Q=32\times 4.184 \times (20-25)\\Q=669.44\ J[/tex]

So, 669.44 J of heat energy is transferred from the water.