By using the relative frequency, we can expect to not roll a "6" in 11 rolls.
We know that in a total of 72 rolls, the outcome is "6" 21 times.
Then the relative frequency is:
F = 21/72 = 0.292
Then we can expect that in N rolls, we will get (0.292)*N times a "6".
So the number of times that we will not get a 6, is:
(1 - 0.292)*N
In this case is N = 15, then we get:
(1 - 0.292)*15 = 10.62
Rounding to the next whole number we get 11, this means that we can expect to not roll a "6" in 11 rolls.
If you want to learn more about relative frequency:
https://brainly.com/question/3857836
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