Answer:
The correct answer is "0.051 N".
Explanation:
Given
Volume,
[tex]V_1=20.0 \ mL[/tex]
[tex]V_2=32.5 \ mL[/tex]
Normality,
[tex]N_1=0.1 \ N[/tex]
[tex]N_2=?[/tex]
As we know,
⇒ [tex]N_1V_1=N_2V_2[/tex]
or,
⇒ [tex]N_2=\frac{N_1V_1}{V_2}[/tex]
On putting the values, we get
⇒ [tex]=\frac{0.1\times 20.0}{32.5}[/tex]
⇒ [tex]=\frac{2}{32.5}[/tex]
⇒ [tex]=0.051 \ N[/tex]
