Respuesta :

MrRoyal

Answer:

The  program in Python is as follows:

nums = []

for i in range(3):

   num = int(input(""))

   nums.append(num)

   

print(min(nums))

Explanation:

This initializes a list of numbers

nums = []

This loop is repeated 3 times

for i in range(3):

For each repetition, this prompts the user for input

   num = int(input(""))

This appends the input to the list

   nums.append(num)

This gets the smallest of the three inputs using the min() function. The smallest is also printed

print(min(nums))

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The Answer is in Bold:

#include <iostream>

using namespace std;

int main() {

 

  int  a, b, c;      //NOTE: you don't have to put a, b, c. you can put it as x, y, z

                                       //or you can make it as num1, num2, num3 etc.

  cin >> a;        

  cin >> b;

  cin >> c;

 

  if (a < b && a < c)   {            

     cout << a <<endl;              

  }                                                    

  else if(b < a && b < c)   {      

     cout << b << endl;

  }

  else   {

     cout << c <<endl;

  }    

  return 0;

}

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