Respuesta :

kkozume27

Answer:

a) There are 4 terms.

b) 2 of them are negative

explanation:

Let's simplify step-by-step.

−3x^2+2y^2+5xy−2y+5x^2−3y^2

=−3x^2+2y^2+5xy+−2y+5x^2+−3y^2

Combine Like Terms:

=−3x^2+2y^2+5xy+−2y+5x^2+−3y^2

=(−3x2+5x^2)+(5xy)+(2y^2+−3y^2)+(−2y)

=2x^2+5xy+−y^2+−2y

Answer:

=2x^2+5xy−y^2−2y

DreameR777

Answer:

Step-by-step explanation:

A. There are 6 terms. Even if there is a variable onto the coefficient, it wouldn't be 2 terms but only 1, in this case, there are 6 terms.

B. If I simplify the number of negative terms, there would be 2 terms.-3x^2,-2y, and -3y^2 are all negative terms in this equation. I can't combine all because one has x as a variable and the other 2 has y. If I simplify both of the negative terms (-2, -3y^2) Ill get -5y^2. -2-3= -5 and just add my other values y and 2 square, and in that case, my final 2 negative terms are -3x^2 and -5y^2

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