Answer:
3.54g Cl-/dm³
Explanation:
To solve this question we must, as first, find the mass of chloride ions finding first, the moles of MgCl2. Then, we must convert the cm³ to dm³ (1cm³ = 0.001dm³).
Moles MgCl2 -Molar mass: 95.211g/mol-
2.38g * (1mol / 95.211g) = 0.0250 moles MgCl2
Moles Cl-:
0.0250 moles MgCl2 * (2mol Cl- / 1mol MgCl2) = 0.0500 moles Cl-
Mass Cl- -Molar mass: 35.45g/mol-:
0.0500 moles Cl- * (35.45g / mol) = 1.77g of chloride ions
dm³:
500cm³ * (0.001dm³ / 1cm³) = 0.500dm³
The concentration is:
1.77g of chloride ions / 0.500dm³ =
