Answer:
[tex]A \to rad/s[/tex]
[tex]B \to rad/s^3[/tex]
Explanation:
[tex]\omega_z(t)=A + Bt^2[/tex]
Required
The units of A and B
From the question, we understand that:
[tex]\omega_z(t) \to rad/s[/tex]
This implies that each of [tex]A[/tex] and [tex]Bt^2[/tex] will have the same unit as [tex]\omega_z(t)[/tex]
So, we have:
[tex]A \to rad/s[/tex]
[tex]Bt^2 \to rad/s[/tex]
The unit of t is (s); So, the expression becomes
[tex]B * s^2 \to rad/s[/tex]
Divide both sides by [tex]s^2[/tex]
[tex]B \to \frac{rad/s}{s^2}[/tex]
[tex]B \to rad/s^3[/tex]
