Answer:
Yes
Step-by-step explanation:
We can test this claim using the one proportion z test :
x = 25 ; n = 100
Phat = x / n = 25 / 100 = 0.25
H0 : P = 0.15
H0 : P > 0.15
The test statistic :
Z = (phat - p) ÷ √p(1-p)/n
Z = (0.25-0.15) ÷ √(0.15*0.85)/100
Z = 2.8
Using the Pvalue from Zscore calculator :
α = 0.05
Pvalue (Z < 2.8) =0.0026
Pvalue < α ; We reject the Null