Answer:
The answer is "[tex]7.90 \ g[/tex]".
Explanation:
Please finds the complete question in the attached file.
[tex]Volume = 10.0 \ mL \\\\Density =0.79 g\ cm^3[/tex]
[tex]\text{Density}=\frac{Mass}{Volume}[/tex]
[tex]Mass = Density \times Volume[/tex]
[tex]=(0.790 g\ cm^3) \times 10.0 \ mL\\\\=7.90 \ g[/tex]
The mass of acetone to be weighed is [tex]7.90 \ g[/tex]
