Answer:
The focus is: [tex](0,2)[/tex]
Step-by-step explanation:
Given
[tex]y = \frac{1}{8}x^2[/tex]
Required
Determine the focus
The focus of a parabola
[tex](x- h)^2 = 4p(y - k)[/tex]
is:
[tex](h,k+p)[/tex]
So, we have:
[tex]y = \frac{1}{8}x^2[/tex]
Cross multiply
[tex]8y = x^2[/tex]
Rewrite as:
[tex]x^2 = 8y[/tex]
Rewrite as:
[tex](x - 0)^2 = 8(y - 0)[/tex]
Express 8 as 4 * 2
[tex](x - 0)^2 = 4 * 2(y - 0)[/tex]
By comparison with: [tex](x- h)^2 = 4p(y - k)[/tex]
[tex]h = 0[/tex] [tex]p =2[/tex] [tex]k = 0[/tex]
So, the focus [tex](h,k+p)[/tex] is:
[tex](h,k+p) = (0,0+2)[/tex]
[tex](h,k+p) = (0,2)[/tex]
