js20009 js20009

04-06-2021
Mathematics

contestada

I would appreciate it so much if anyone helps me on these answers please!

I would appreciate it so much if anyone helps me on these answers please class=

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jimrgrant1 jimrgrant1

04-06-2021

Answer:

see explanation

Step-by-step explanation:

(14)

tan F = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{GH}{FH}[/tex] = [tex]\frac{12}{5}[/tex]

(15)

sin G = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{FH}{FG}[/tex] = [tex]\frac{5}{13}[/tex]

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