Answer:
[tex]\huge\boxed{Answer\hookleftarrow}[/tex]
Given,
[tex]3x - 2y = 5[/tex]
[tex]xy = - 2[/tex]
Now,
[tex](3x - 2y) {}^{2} = (5) {}^{2} \\ [/tex]
Use the algebraic identity ⇻ (a - b)² = a² - 2ab + b²
[tex](3x - 2y) {}^{2} = (5) {}^{2} \\ 3x {}^{2} - 2 \times 3x \times 2y + 2y {}^{2} = 5 {}^{2} \\ 9 {x}^{2} - 12xy + 4y {}^{2} = 25 \\9x {}^{2} + 4y {}^{2} = 25 + 12xy \\ 9x {}^{2} + 4 {y}^{2} - 1 = 24 + 12xy[/tex]
✐ So, the value of 9x² + 4y² - 1 is 24 + 12xy
Now,
xy = - 2
So, 12xy = 12 × - 2 = - 24
•°• 24 + 12xy
= 24 + (-24)
= 24 - 24
= 0
⎆ The value of 9x² + 4y² - 1 is 0.
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# ꧁❣ RainbowSalt2²2² ࿐
