Suppose a triangle has sides a, b, and c, and that a2 + b2 > c2. Let 0/ be the
measure of the angle opposite the side of length c. Which of the following
must be true? Check all that apply.
A. 0/ is an acute angle.

B. cos 0/ > 0

C. The triangle is a right triangle.

D. The triangle is not a right triangle.

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caylus caylus · Answer 1 · 2021-07-01T19:23:31+02:00

Hello,

Answer A

Indeed:

[tex]c^2=c^2+b^2-2ab*cos(\theta) < a^2+b^2\\\\-cos(\theta)<0\\\\cos(\theta)>0\ \Longrightarrow \theta < 90^o[/tex]

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sheenuvt12 sheenuvt12 · Answer 2 · 2022-07-25T08:50:39+02:00

True statements are:

A. [tex]\theta[/tex] is an acute angle.

C. The triangle is a right triangle.

D. The triangle is not a right triangle.

An angle is a combination of two rays (half-lines) with a common endpoint.

Given:

a² + b² > c²

as, the triangle with sides a, b and c.

If this is a right triangle, then the condition a² + b² > c² apply.

Using cosine law.

angle> 90 degrees which is an obtuse angle.

Also, cos [tex]\theta[/tex] is negative.

Hence, the conditions that are true are A, C and D.

Learn more about this concept here:

https://brainly.com/question/1619127

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