Answer:
the distance is 16
Step-by-step explanation:
Hi there!
We are given point A (-4,-13) and point B (-4,3). We need to find the distance between those two points
the distance formula is given as [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}[/tex] where ([tex]x_{1}[/tex],[tex]y_{1}[/tex]) and ([tex]x_{2}[/tex], [tex]y_{2}[/tex]) are points
we are given 2 points, which is what we need for the formula. However, let's label the values of the points to avoid any confusion
[tex]x_{1}[/tex]=-4
[tex]y_{1}[/tex]=-13
[tex]x_{2}[/tex]=-4
[tex]y_{2}[/tex]=3
now substitute those values into the formula. Remember: the formula uses SUBTRACTION.
[tex]\sqrt{(-4--4)^2+(3--13)^2}[/tex]
simplify
[tex]\sqrt{(-4+4)^2+(3+13)^2}[/tex]
now add the values inside the parenthesis that are under the radical
[tex]\sqrt{(0)^2+(16)^2}[/tex]
raise everything under the radical to the second power
[tex]\sqrt{0+256}[/tex]
add under the radical
[tex]\sqrt{256}[/tex]
now take the square root of 256
[tex]\sqrt{256}[/tex]=16
so the distance between point A and point B is 16
Hope this helps! :)