Given:
The equation is:
[tex]y-5=\dfrac{4}{3}(x-5)[/tex]
To find:
The graph of the given equation.
Solution:
Point slope form of a line is:
[tex]y-y_1=m(x-x_1)[/tex] ...(i)
We have,
[tex]y-5=\dfrac{4}{3}(x-5)[/tex] ...(ii)
On comparing (i) and (ii), we get
[tex]x_1=5,y_1=5,m=\dfrac{4}{3}[/tex]
It means, slope of the line is [tex]\dfrac{4}{3}[/tex] and it passes through the point (5,5).
Putting x=2 in the given equation, we get
[tex]y-5=\dfrac{4}{3}(2-5)[/tex]
[tex]y=\dfrac{4}{3}(-3)+5[/tex]
[tex]y=-4+5[/tex]
[tex]y=1[/tex]
The line passes through the point (2,1). Plot the points (2,1) and (5,5) on a coordinate plane and connect them by a free hand curve as shown below.
