Answer:
Calculate the volume (in L) occupied by 3.40 g of NH3 at STP. (STP: 0 degree Celsius and 1 atmosphere of pressure).
Explanation:
To get the volume of ammonia gas at STP, calculate the number of moles of [tex]NH_3[/tex] in the given amount.
Number of moles of [tex]NH_3[/tex] gas is:
[tex]number of moles of NH_3 gas&=\frac{given mass of the gas}{its molecular mass} \\ &=\frac{3.40g}{17.0g/mol} \\&=0.2 mol.[/tex]
Since,
1 mol of any gas at STP occupies ------- 22.4 L of volume.
then,
0.2 mol of [tex]NH_3[/tex] occupies how much volume?
[tex]=>0.2 mol x \frac{22.4 L}{ 1.0 mol} \\=4.48 L[/tex]
Hence, the volume occupied by 3.40 g of ammonia at STP is --- 4.48 L.
