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Mu Alpha Theta, a math honorary club, wants to raise money. The club plans to sell cards and bouquets of flowers for Valentine's Day. Cards cost the club $2 each; bouquets cost the club $3.50 each. Mu Alpha will sell the cards for $6 each, and the flowers for $8 each. The club can spend $360 to buy the cards and the flowers. It wants to collect $900 from its sales. Which linear equation represents this scenario?

A. 2x + 3.5y =360; 6x -8y =900
B. 2x + 3.5y = 360; 8x + 6y = 900
C. 2x - 3.5y = 360; 6x + 8y = 900
D. 2x + 3.5y = 360; 6x + 8y = 900
E. 2x + 6y = 360; 3.5x + 8y = 900
F. No equation.

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Respuesta :

hicata2007 hicata2007 · Answer 1 · 2021-10-27T02:58:24+02:00

Answer:

900

Step-by-step explanation:

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bhoopendrasisodiya34 bhoopendrasisodiya34 · Answer 2 · 2022-07-20T11:37:31+02:00

2x+3.5y=360 and 6x+8y=900 are two linear equation that represents the given scenario.

We need to find the linear equations for the given situation.

Equations involving two or more unknowns that are to have the same values in each equation.

Let the number of cards be x and the number of flowers be y.

Cards cost the club $2 each; bouquets cost the club $3.50 each. The club can spend $360 to buy the cards and the flowers.

Now, 2x+3.5y=360

Mu Alpha will sell the cards for $6 each, and the flowers for $8 each. It wants to collect $900 from its sales.

Now, 6x+8y=900

Therefore, 2x+3.5y=360 and 6x+8y=900 are two linear equation that represents the given scenario.

To learn more about linear equations visit:

https://brainly.com/question/11897796.

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