Answer:
The two solutions are
(0,-4) and (-1,-6)
Step-by-step explanation:
The ys have to be equal so you can equate the right hand side.
x^2 + 3x - 4 = 2x - 4 Add 4 to both sides
x^2 + 3x = 2x Subtract 2x from both sides
x^2 + 3x - 2x = 0 Combine
x^2 + x = 0 Factor
x(x + 1) =0
Just to show you that these two points really are the solutions, you can see the graph below
x has 2 values
x + 1 = 0
x = - 1
or
x = 0
Now solve for y
y = 2x - 4
Let x = 0
y = - 4
Let x = - 1
y = 2x - 4
y = -2 - 4
y = - 6
The blue is y = x^2 + 3x - 4
The green line is y = 2x - 4
