it was helpful to you:
[tex]3 {x}^{2} + 3 {y}^{2} - 48x + 60y + 384 = 0 \\ \\ (x - a) {}^{2} + (y - b) {}^{2} = {r}^{2} \\ is \: the \: circle \: equcation \\ with \: a \: radius \: r \: centered \\ at \: (a \: b) \\ \\ rewrite \: 3 {x}^{2} + 3 {y}^{2} - 48x + 60y + \\ 384 = 0 \: in \: the \: standard \: of \: \\ circle \: equation \\ (x - {8}^{2} ) + (y - ( - 10)) {}^{2} \\ \\ therefore \: the \: circle \: properties \\ \: are \: (a \: b) = (8 \: - 10) \: r = 6 \\ \\ answer \: is \: (8 \: - 10) \: r = 6[/tex]
