Let numerator be x
ATQ
[tex]\\ \sf\longmapsto x+x+2=12[/tex]
[tex]\\ \sf\longmapsto 2x+2=12[/tex]
[tex]\\ \sf\longmapsto 2x=12-2[/tex]
[tex]\\ \sf\longmapsto 2x=10[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{10}{2}[/tex]
[tex]\\ \sf\longmapsto x=5[/tex]
Now the fraction is
[tex]\\ \sf\longmapsto \dfrac{x}{x+2}[/tex]
[tex]\\ \sf\longmapsto \dfrac{5}{5+2}[/tex]
[tex]\\ \sf\longmapsto \dfrac{5}{7}[/tex]
-- Their sum is 12.
-- If they were equal, each would be 6.
-- To make them differ by 2 without changing their sum, move 1 from the numerator (make it 5), to the denominator (make it 7).
