Answer:
The electrical energy stored in the capacitor will be cut in half.
Explanation:
The energy in a capacitator is given by E=C[tex]V^{2}[/tex]/2 and the formula for the Capacitance in a capacitator is C= [tex]\frac{Q}{V}[/tex] = ε[tex]\frac{A}{d}[/tex] .
So if we replace C = ε[tex]\frac{A}{d}[/tex] in the first equation we have:
E = ε[tex]\frac{AV^{2} }{2d}[/tex]